![y = x^2 + 2x + 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/k51ghuw8iwqk8okj8oreojr8mbpy9xfj6e.png)
It's already a square; we don't need to add anything to complete the square.
![y = (x + 1)^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/e0i36cq8tmvi1kvhe0kq1pbfyyivkrumdu.png)
That's a vertex at x = -1. The corresponding y is y=0.
Answer: Vertex at (-1,0)
As for the other questions cut off there, the axis is the vertical line x = -1 and the range is y ≥ 0.