The value of x will be 8.65 or 0.35
Solution:
Given,
![x^2-9x+3=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jlzosnkmozx392krt3nsx9t487l1vl9r5z.png)
Here, to solve the given equation, we have to use the quadratic formula,
![x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a} \text{ when } a x^(2)+b x+c=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/55cl5wu281n7waicrt9wzg7pbqoyh3vrqe.png)
where a=1; b=-9; c=3 and x is the value to be found.
On substituting the values in the equation we get,
![\bold{x=(-(-9)\pm√((-9)^2-4*3*1))/(2*1)} \bold{\rightarrow (9\pm√(81-12))/(2)}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rvejvzsho8c5kj3icwt47lr4hh8fnzki97.png)
\bold{\Rightarrow \frac{9\pm\sqrt{69}}{2}}}
The square root of 69 is 8.3
On substituting the value in the above equation we get,
![\bold{\Rightarrow (9+8.3)/(2)}} \bold{ \text{ or }} \bold{ (9-8.3)/(2)}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1se8mfbr7ngjn7t37v9sx5fploxzgg05iq.png)
On solving we get,
![\bold{\Rightarrow (17.3)/(2)}} \bold{ \text{ or }} \bold{ (0.7)/(2)}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bpaadtzk8jm4oallixcajn3zu8acs910j9.png)
![\bold {\Rightarrow \therefore \text{ x will be }} \bold{8.65} \bold{\text{ or }} \bold{0.35}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r7jwm1hv3oacgt0c3pqses5ewe72j798nq.png)