Question

A ball is kicked from the ground into the air at a velocity of 3 m/s at an angle 35° above the horizontal and hits the ground some time later. What is the magnitude of the average velocity of the ball between the time it’s kicked and the time it lands?

Answer 1

Answer:2.45 m/s

Step-by-step explanation:

Given

Launch velocity
`(u)=3 m/s`

launch angle
`=35^(\circ)`

as the vertical velocity first decreasing to zero and then increases to original value so its avg is zero .

`v_(avg)=(displacement)/(time)`

`v_(avg)=(Range)/(time)`

`v_(avg)=(u\cos \theta * t)/(t)`

thus
`v_(avg)=(3\cos 35* t)/(t)`

`v_(avg)=3\cos 35=2.45 m/s`