Question

What is the mass, in grams, of solute in 255mL of a 0.0525M solution of KMnO4 (MM =

158.04g/mol)?

Answer 1

Mass = 2.12 g

Step-by-step explanation:

Given data:

Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)

Molarity = 0.0525 M

Mass in gram = ?

Solution:

First of all we will calculate the number of moles.

Molarity = number of moles of solute / volume in litter

0.0525 M = number of moles of solute / 0.255 L

Number of moles of solute = 0.0525 M ×0.255 L

Number of moles of solute = 0.0134 mol

Mass in gram:

Number of moles = mass/ molar mass

Mass = moles × molar mass

Mass = 0.0134 mol × 158.04 g/mol

Mass = 2.12 g