Question

2 KClO_2 produces 2 KCl+ 3O_2 when heated. If this reaction produces 82.8 g of KCl how many grams of O2 were produced?

Answer 1

37.046 grams of oxygen gas were produced.

Step-by-step explanation:

`2KClO_2\rightarrow 2KCl+ 3O_2`

Moles of potassium chlorite =
`(82.2 g)/(106.5 g/mol)=0.7718 mol`

According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.

Then 0.7718 moles of potassium chlorite will give:

`(3)/(2)* 0.7718 mol=1.1577 mol` of oxygen gas.

Mass of 1.1577 moles of oxygen gas:

1.1577 mol × 32 g/mol = 37.046 g

37.046 grams of oxygen gas were produced.