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Factor completely
-2x^4 + 14x^2 - 24

1 Answer

2 votes

Answer:


-2[x^2 - 3][x - 2][x + 2]

Explanation:


(-2x^4 + 8x^2) + (6x^2 - 24) \\ -2x^2(x^2 - 4) \: \: \: \: 6(x^2 - 4) \\ \\ (-2x^2 + 6)(x^2 - 4) \\ \\ -2(x^2 - 3)(x - 2)(x + 2)

For this exercise, you have to use the Difference of Squares
[a^2 - b^2 = [a - b][a + b]].

I am joyous to assist you anytime.

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