Question

A microwave oven operates at 2.4 GHz with an intensity inside the oven of 2300 W/m2 . Part A What is the amplitude of the oscillating electric field? Express your answer with the appropriate units. E0E 0 = nothing nothing Request Answer Part B What is the amplitude of the oscillating magnetic field? Express your answer with the appropriate units. B0B 0 = nothing nothing

Answer 1

`4.38958* 10^(-6)\ T`

`1316.874\ V/m`

Step-by-step explanation:

`\mu_0` = Vacuum permeability =
`4\pi * 10^(-7)\ H/m`

I = Flux = 2300 W/m²

c = Speed of light =
`3* 10^(8)\ m/s`

Amplitude of the oscillating magnetic field

`B_0=\sqrt{(2\mu_0I)/(c)}\\\Rightarrow B_0=\sqrt{(2* 4\pi * 10^(-7)* 2300)/(3* 10^8)}\\\Rightarrow B_0=4.38958* 10^(-6)\ T`

The amplitude of the oscillating magnetic field is
`4.38958* 10^(-6)\ T`

Amplitude of the oscillating electric field

`E_0=c* B_0\\\Rightarrow E_0=3* 10^(8)* 4.38958* 10^(-6)\\\Rightarrow B_0=1316.874\ V/m`

The amplitude of the oscillating electric field is
`1316.874\ V/m`