Question

Find an equation for the line with slope m=10/11and which goes through the point (33,-6)​

Answer 1

The answer is: y = 10/11x - 36

Explanation:

Use the point slope form of the equation to start:

y - y1 = m(x - x1)

Then replace the variables with the givens:

y - (-6) = 10/11(x -33)

Solve for y:

y + 6 = 10/11x - 330/11

y = 10/11x - 330/11 - 6

y = 10/11 - 330/11 - 66/11

y = 10/11 - 396/11

y = 10/11x - 36