Question

when a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm. let 2.0 cm be the rest position for the mass-spring system. the mass is then pulled down an additional distance of 1.5 cm and released.calculate the period of resulting oscillation in si units.

Answer 1

To find the period of oscillation for the mass-spring system, we can use the formula T=2π√(m/k), where T is the period, m is the mass, and k is the spring constant. With the known mass and spring displacement, the spring constant can be determined using Hooke's law, and then used to calculate the period.

Step-by-step explanation:

To find the period of oscillation for the mass-spring system, we can use the formula T=2π√(m/k), where T is the period, m is the mass, and k is the spring constant. In this case, the spring constant is related to the spring's stretch by Hooke's law, F=kx, where F is the force, k is the spring constant, and x is the displacement. The force experienced by the spring due to the additional displacement of 1.5 cm can be calculated as F=kx. With the mass known, we can determine the spring constant by rearranging the equation F=kx and solving for k. Once we have the spring constant, we can substitute it along with the mass into the formula T=2π√(m/k) to find the period of oscillation in SI units.