Question

How do you write y+1=4/5(x-3) in standard form?

Answer 1

The standard form of the given expression is
`- ((4)/(5))x + y +  ((17)/(5))   = 0`

Explanation:

Here, the given expression is
`y + 1 = (4)/(5)  (x-3)`

Now, the Standard Form of the equation is ax + by + c = 0

Solving this, we get:

`y + 1 = (4)/(5)  (x-3)  \implies y + 1 = ((4)/(5))x  - (12)/(5)`

⇒
`y + 1   - ((4)/(5))x + ((12)/(5))  = 0`

or,
`y  - ((4)/(5))x + ((12)/(5)  + 1 )= 0  \implies y  - ((4)/(5))x + ((12+ 5)/(5))   = 0`

⇒
`y  - ((4)/(5))x + ((17)/(5))   = 0`

Hence, the standard form of the given expression is
`- ((4)/(5))x + y + ((17)/(5))   = 0`