Answer:
![4p^4+6p+5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tdgq04mbbm53up50398cnvbhiyc5b2hdhg.png)
Explanation:
Given
![(12p^5+20p^4+18p^2+45^p+25)/(3p+5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tgylegateon7av203qg2ztxh5i136mpvxx.png)
Step 1:
Now Dividing the above Equation our first quotient will be
and First remainder will be
![18p^2+45p](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3e3tvz1pjjegiobt3v8hol7xy2q3g0tzn0.png)
Step 2:
Now Dividing the First remainder
with
![3p+5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rgtkjj83rt3yown961cu4g0mgmm9xd6zd2.png)
now our second Quotient will be
and Second remainder will be
![15p+25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7hh8fxpqro1pl8vhjsvii3s9b975rsw4fa.png)
Step 3:
Now Dividing Second remainder
with
![3p+5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rgtkjj83rt3yown961cu4g0mgmm9xd6zd2.png)
now our third Quotient will be
and Remainder will be 0.
Our Final Answer is
with remainder 0