Answer:
Step-by-step explanation:
Power Dissipated in a resistor is given by two methods i.e.
and
![P=I^2\cdot R](https://img.qammunity.org/2020/formulas/physics/high-school/mbyo1igu1iie16m6u2lslkf9e282f7wcq7.png)
where
![V=Potential\ difference](https://img.qammunity.org/2020/formulas/physics/high-school/hy7j4c160rob7s8rjzfvl91jjgfitcx1sc.png)
![R=resistor](https://img.qammunity.org/2020/formulas/physics/high-school/c74b4d291ov7uvm94o285n90b26lvaxaps.png)
![I=current](https://img.qammunity.org/2020/formulas/physics/high-school/8qvq0qdok4ru0rlb7rlozu3v80i34ai65a.png)
both formula gives Power but Former is used when voltage is constant i.e. when resistors are in parallel and the later is used when the resistor are in series .
Though
can also be used in series but we have to calculate the Potential drop across each resistor then we can apply the formula.
Similar is with
![P=I^2R](https://img.qammunity.org/2020/formulas/physics/high-school/f35m14q57qc21dskkjzvdygp4lfysp391s.png)
First we have to calculate current through each resistor then we can apply the Formula