Question

an NHL hockey player (m=90 kg) stands motionless on the ice . the 10 kg stanley cup is thrown to the player at 4m/s. after he catches the cup determine the speed of the player cup combination. assuming there is no friction between the skates and the ice?

Answer 1

Answer:v=0.4 m/s

Step-by-step explanation:

Mass hockey player
`m_1=90 kg`

mass of cup
`m_2=10 kg`

Velocity of cup
`u=4 m/s`

let v be the velocity of the combined system

Conserving momentum

`m_1\cdot 0+m_2u=(m_1+m_2)v`

`v=(10* 4)/(100)`

`v=(40)/(100)`

`v=0.4 m/s`