Question

A deli ordered 6 1/2 wheels of cheese .Over the weekend 3 5/8 wheels of cheese were sold.On Tuesday another wheels were sold.How much cheese was left for Wednesday

Answer 1

`1(7)/(8)` wheels of cheese.

Step-by-step explanation:

We have been given that a deli ordered 6 1/2 wheels of cheese. Over the weekend 3 5/8 wheels of cheese were sold. On Tuesday another wheels were sold.

To find the cheese left for Wednesday, we will subtract 3 5/8 and 1 from 6 1/2 as:

`\text{Cheese left for Wednesday}=6(1)/(2)-3(5)/(8)-1`

Convert mixed fraction into improper fraction:

`\text{Cheese left for Wednesday}=(2* 6+1)/(2)-(3* 8+5)/(8)-1`

`\text{Cheese left for Wednesday}=(13)/(2)-(29)/(8)-1`

Make a common denominator:

`\text{Cheese left for Wednesday}=(13* 4)/(2* 4)-(29)/(8)-(1* 8)/(8)`

`\text{Cheese left for Wednesday}=(52)/(8)-(29)/(8)-(8)/(8)`

Combine numerators:

`\text{Cheese left for Wednesday}=(52-29-8)/(8)`

`\text{Cheese left for Wednesday}=(15)/(8)`

`\text{Cheese left for Wednesday}=1(7)/(8)`

Therefore,
`1(7)/(8)` wheels of cheese was left for Wednesday.