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What is the equation of a line perpendicular to y=1/2x+5 and passes through the point (3,-2)

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Answer:

The Answer is: y = -2x + 4

Explanation:

The given equation for a line:

y = 1/2x + 5

The given point: (3, -2)

The slope is 1/2

The slope of a perpendicular line is the negative inverse: -2

Use the point slope equation for a line:

y - y1 = m(x - x1)

y - (-2) = -2(x - 3)

y + 2 = -2x + 6

Subtract 2 from each side:

y = -2x + 4

User Vikram Parimi
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