Question

A rectangular loop with dimensions 4.20 cm by 9.50 cm carries current I. The current in the loop produces a magnetic field at the center of the loop that has magnitude 3.10×10−5 T and direction away from you as you view the plane of the loop. Part A What is the magnitude of the current in the loop?

Answer 1

I=1.48 A

Step-by-step explanation:

Given that

B=3.1 x 10⁻5 T

b= 4.2 cm

l= 9.5 cm

The relationship for magnetic field and current given as

`B=(2\mu _oI)/(\pi)D`

Where

`D=(√(l^2+b^2))/(lb)`

By putting the values

`D=(√(l^2+b^2))/(lb)`

`D=(√(0.042^2+0.095^2))/(0.042* 0.095)`

D=26.03 m⁻¹

`B=(2\mu _oI)/(\pi)D`

`3.1* 10^(-5)=(2* 4* \pi * 10^(-7) I)/(\pi)* 26.03`

`I=\frac{3.1* 10^(-5)}{{2* 4* 10^(-7) }* 26.03}`

I=1.48 A