Answer:
The negative solution k = -1 is the desired solution.
Explanation:
Let the given number = k
So, according to the question:
![k^(2) - 9 = 8k](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l4qk0burstj2v43me1t1hpzs2wvqupnf2j.png)
or,
![k^(2) - 8k - 9 = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ldzbd97p7xntte3a6mb3pzfkux53bz6f43.png)
Now, solving this quadratic equation, we get
![\implies k^(2) - 9k + k - 9 = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kixx7w056mzw0jhqkrxgazhc1bbltmdv2h.png)
or, k ( k-9) + 1 (k-9) = 0
⇒( k-9)(k+1) = 0
or, ( k-9) = 0 , or (k+1) = 0
⇒ k = 9 or k = -1
Since we only want the negative solution , the k = -1 is the desired solution.