Question

S8 + 12O2 = ​​​8SO3

​If it takes 36.72 grams of O2 to begin the reaction, how many grams of SO3 will be formed?

Answer 1

• 12mol of O_2 forms 8 moles of SO_3
• 3mol of O_2 forms 2mol of SO_3
• 1mol of O_2 forms 0.6mol of SO_3

Lets calculate moles of O_2

`\\ \sf\longmapsto (Given\:mass)/(Molar\:mass)`

`\\ \sf\longmapsto (36.72)/(32)`

`\\ \sf\longmapsto 1.14mol`

moles of SO_3

• 1.14(0.6)=0.684mols

Mass of SO_3

`\\ \sf\longmapsto 0.683(80)=54.6g`