Question

Anyone know the answer to this algebra 2 question?

Answer 1

The answer to your question is: I(dB) = 320

Explanation:

Data

I(dB) = 10log(
`(I)/(Io)`)

I = intensity of a given sound

Io = hearing intensity

if I = 10³²(Io) find I(dB)

Process

Substitute the value of I in the equation given and simplify using logarithms rules.

l(dB) =
`10 log (10^(32)Io )/(Io)`

Eliminate Io

I(dB) = 10 log (10³²)

Use the rule of powers in logarithms

I(dB) = 10(32)log(10)

l(dB) = 320(1)

I(dB) = 320