Question

Calculate the specific heat of water if 16.736 J of energy are required to heat 2.000

g of water by 2.000°C.

4,184 J/g.°C

4.184 J/g.°C

8.401 J/g °C

8401 J/g.

Answer 1

The specific heat of water is Cp = 4.184
`(J)/(g.^(o)C)`

Step-by-step explanation:

1. The specific heat can be expressed as:

`Cp=(Q)/(m(T_(2)-T_(1)))`

where Q is the energy, m is the mass of water, and T2-T1 express the change in the temperature.

2. Replace values for mass, energy and temperature:

`Cp=(16.736J)/((2.000g)*2.000^(o)C)}`

3. Solve the equation to obtain the specific heat of water:

Cp=4.184
`(J)/(g.^(o)C)`