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A rock band playing an outdoor concert produces sound at 120 dB 5.0 m away from their single working loudspeaker. Ignore sound reflected from walls and other objects and consider sound originating directly from the speakers.

a. What is the sound intensity level 35 m from the speaker?
b. How far away from the speaker should you stand to ensure the intensity does not exceed 80 dB?

User TomerBu
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1 Answer

6 votes

Answer:

Given that

β= 120 dB at 5 m

We know that sound intensity given as


\beta =10dB\log(I)/(I_o)


120 =10\log(I)/(10^(-12))

I= 1 W/m²

Power producing by loud speaker

P = I x 4πr²


P=1* 4\pi * 5^2\ W

P=314.15 W

a)

Let take intensity at 35 m is I'

r'=35 m

I'=P/4πr'²


I'=(314.15)/(4\pi * 35^2)\ W/m^2

I'=0.0204 W/m²

b)

Given that

β'= 80 dB


\beta' =10dB\log(I')/(I_o)


80=10\log(I')/(10^(-12))

I'=10⁻⁴ W/m²

Let's take at distance r intensity is 80 dB

P=314.15 W

P = I' x 4πr'²

314.15 = 10⁻⁴ x 4πr'²

r'=500.11 m

User Ahmed Elgammudi
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