The correct arranged order from least to greatest is pi/3, | -1.7 |, 3 sqrt {5}/2
Solution:
Given, numbers are |-1.7|, pi/3, 3sqrt {5}/2
We have to arrange the given set of numbers in an order
Now, as we can see, they are in different forms, so first let us convert them into decimal form.
The absolute value or modulus |x| of a real number "x" is the non-negative value of "x" without regard to its sign
Hence | -1.7 | = 1.7
Now take pi/3
We know that value of
![pi (\pi) = 3.14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v0ehutcqp9uyig6ppls8a5mrckhkxez3cn.png)
hence
![pi/3 = (3.14)/(3) = 1.0467](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g6z91kd24uoe0zjixz0o99djdy7xx8at0i.png)
Now take 3sqrt {5}/2
![(3 √(5))/(2)=(3 * 2.236)/(2)=3.354](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h41qvyl34pfxbu8hhkxtwmn5uxlckvz82r.png)
Now comparing the values, we can order from least to greatest
1.0467 < 1.7 < 3.354
So, arranged order is pi/3, | -1.7 |, 3 sqrt {5} / 2