Question

A man pushes a 49 kg mower with a force of 650 N at a downward angle of 35° as shown in the picture to the right. If the mower experiences a frictional force of 493.249 N, find:

The acceleration of the mower.
The normal force acting on the mower.

Answer 1

a = 0.8m/s^2

F = 39.28 N

Step-by-step explanation:

Sum of forces in X direction = 650cos(35)N-493.249N

Sum of forces in X direction= 39.28 N

F = m*a

a = F/m

a = 39.28N/49kg

a = 0.8 m/s^2