Answer:
D) No, since kinetic energy is not conserved.
Step-by-step explanation:
Since momentum is always conserved in all collision
so in Y direction we can say
![0 = m(3.5 sin30) - mv_y](https://img.qammunity.org/2020/formulas/physics/high-school/hrzdb26pu4wun2mqcqr6wqz1m1l3wea91n.png)
![v_y = 1.75 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/hf3pqwr7nx3kuhgisti4z6a2fje9fjn2g1.png)
Now similarly in X direction we will have
![m(4.5) = m(3.5 cos30 ) + mv_x](https://img.qammunity.org/2020/formulas/physics/high-school/4c0cm7cu4cdfhl19q2j7i26sdrmbmo478g.png)
![v_x = 1.47 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/nn5pfhex9qlrvf9fp6se3g7nqrlwjhbwjq.png)
now final kinetic energy of both puck after collision is given as
![KE_f = (1)/(2)m(3.5^2) + (1)/(2)m(1.75^2 + 1.47^2)](https://img.qammunity.org/2020/formulas/physics/high-school/2enpiom9ifpyul60mkw3ygsvsntvqu7n93.png)
![KE_f = 8.73 m](https://img.qammunity.org/2020/formulas/physics/high-school/79pswjfjoqp48yk4u5ljxcxftszrepdjnu.png)
initial kinetic energy of both pucks is given as
![KE_i = (1)/(2)m(4.5^2) + 0](https://img.qammunity.org/2020/formulas/physics/high-school/zajw5oy70tsw7mc4r3hi9cd5tjrdcpy871.png)
![KE_i = 10.125 m](https://img.qammunity.org/2020/formulas/physics/high-school/4asxh573iv1vcev2ugi167bafcylhytmge.png)
since KE is decreased here so it must be inelastic collision
D) No, since kinetic energy is not conserved.