Question

Freon−12 (CF2Cl2), widely used as a refrigerant and aerosol propellant, is a dangerous air pollutant. In the troposphere, it traps heat 25 times as effectively as CO2, and in the stratosphere, it participates in the breakdown of ozone. Freon−12 is prepared industrially by reaction of gaseous carbon tetrachloride with hydrogen fluoride. Hydrogen chloride gas also forms. How many grams of carbon tetrachloride are required for the production of 45.6 dm3 of Freon−12 at 21°C and 1.77 atm?

Answer 1

514.76 grams of carbon tetrachloride are required.

Step-by-step explanation:

P = Pressure of vapor = 1.77 atm

V = Volume of vapor =
`45.6 dm^3` = 45.6 L

n = number of moles of Freon-21 = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of vapor = 21°C = 294.15 K

PV = nRT( ideal gas equation)

`(1.77 atm)* 45.6 L=n* (0.0821L.atm/mol.K)* 294.15 K\\\\n=3.3426 mole`

`CCl_4+2HF\rightarrow CF_2Cl_2+2HCl`

Moles of Freon-21 = 3.3426 mol

According to reaction, 1 mol of Freon-21 is obtained from 1 mole of carbon tetrachloride.

Then 3.3426 moles of Freon-21 will be obtained from:

`(1)/(1)* 3.3426 mol=3.3426 mol`

Mass of 3.3426 moles of carbon tetrachloride:

3.3426 mol × 154 g/mol = 514.76 g

514.76 grams of carbon tetrachloride are required.