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Given: PQ= TQ, UQ: QS

Prove: PS TU

Reasons

Statements

1. PQ= TO, UQ= OS

2. PQ = TQ, UQ = QS

3. PQ+ QS = PS; TQ + QU = TU

4. TQ + QS = PS

5. TQ + QS = TU

6. PS = TU

7. PS = TU

1. Given

2. reflexive Ž

3. Addition Poe

4. Seament Addition post

5. Seament Addition Post

6. U

7. Definition of Congroencel

Gina Wilson (All Things Algebra), 2014

1 Answer

2 votes

Answer:

The required prove is shown below.

Explanation:

Consider the provided statement.

The required figure is shown below:

Statement Reasons

PQ ≅ TQ; UQ ≅ QS Given

PQ = TQ, UQ = QS Definition of Congruence

PQ + QS = PS; TQ+QU = TU Segment Addition Postulate

TQ + QS = PS Substitution (PQ = TQ)

TQ + QS = TU Substitution (QU = QS)

PS = TU Transitive Property

Prove: PS ≅TU Definition of Congruence

Hence, the required prove is shown above.

Given: PQ= TQ, UQ: QS Prove: PS TU Reasons Statements 1. PQ= TO, UQ= OS 2. PQ = TQ-example-1
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