Question

Find the solutions to y = (x – 1)2 for x = –3, 0, and 3. (–3, –2), (0, 1), (3, 4) (–3, –16), (0, 1), (3, 4) (–3, 16), (0, 1), (3, 4) (–3, –4), (0, –1), (3, 2)

Answer 1

The pairs of ( x,y) are ( -3 ,16) , ( 0,1) and ( 3,4)

Explanation:

y = ( x -1)²

y = x² - 2 x + 1

for x = -3

y =( -3)² - 2 × -3 + 1

= 9 +6 +1

= 16

so ( x, y) = ( -3 , 16)

for x = 0

y = 0² - 2 ×0 + 1

= 1

so ( x,y) = ( 0,1)

For x = 3

y = 3² - 2 × 3 +1

= 9 - 6 +1

= 4

( x,y) = (3 , 4)

so the pairs of ( x,y) are ( -3 ,16) , ( 0,1) and ( 3,4)