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Solve 3x^2 + 6x+15=0

User Irpbc
by
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1 Answer

7 votes

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x =
\frac{-b\pm \sqrt{b^(2)-4ac}}{2a}

So , from given eq , the value of x is now obtain as

x =
\frac{-b\pm \sqrt{b^(2)-4* a* c}}{2* a}

Or, x =
\frac{-6\pm \sqrt{6^(2)-4* 3* 15}}{2* 3}

Or, x =
(√(-144) )/(6)

∴ x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i ) Answer

User Schcriher
by
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