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\left \{ {{j+k=7} \atop {j-k=3}} \right.

Use the substitution method.

A. There is no solution.
B. The solution is (8, 1).
C. There are an infinite number of solutions.
D. The solution is (5, −2).

1 Answer

7 votes

Answer: I got it to you fast no flash

The first given equation is:

j + k = 3

This can be rewritten as:

j = 3 - k .................> I

The second given equation is:

j - k = 7 ............> II

Substitute with I in II and solve as follows:

j - k = 7

(3-k) - k = 7

3 - 2k = 7

-2k = 7-3 = 4

k = 4/-2

k = -2

Substitute with k in I to get the value of J as follows:

j = 3 - k

j = 3 - (-2) = 3+2

j = 5

Based on the above, the solution is (5,-2)

User Egret
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