Question

In a population the homozygous dominant individuals make up 81% of the population, heterozygous individuals make up 18%, and homozygous recessive individuals make up 1%. What is the frequency of the "p" allele?

Answer 1

p=0.9

Step-by-step explanation:

The frequency of the different genotypes is as follows:

• AA = 0.81
• Aa = 0.18
• aa = 0.01

There are 2 alleles for this gene, the dominant allele A appears twice in the homozygous dominant genotype and once in the heterozygous.

Then, the frequency of the A allele, p, can be calculated as:

p= freq(AA) + freq(Aa)/2

p= 0.81 + 0.18/2

p=0.9