Question

A uniform hoop rolls without slipping down a 20° inclined plane. What is the acceleration of the hoop's center of mass? The moment of inertia of a uniform solid disk about an axis that passes through its center = mr2 The moment of inertia of a uniform solid disk about an axis that is tangent to its surface = 2mr2. X3.35 m/s2

Answer 1

The acceleration of the hoop's center of mass is 3.35 m/s².

Step-by-step explanation:

Given that,

Angle = 20°

We need to calculate the acceleration of the hoop's center of mass

Using formula of vertical component

`F = mg\sin\theta`....(I)

Here, F = ma

Put the value of F in equation (I)

`ma=mg\sin\theta`

Put the value into the formula

`a=9.8*\sin20`

`a=3.35\ m/s^2`

Hence, The acceleration of the hoop's center of mass is 3.35 m/s².