First of all, let's consider the line, since it's simpler to graph: we draw the endpoints and connect them:
![f(x)=2-(3x)/(4\pi) \implies f(0)=2,\quad f(2\pi)=(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zjji5bls5lp6tqkhopcbzkd4yhj3ace93k.png)
So, you just need to draw the points
![(0,2),\quad \left(2\pi, (1)/(2)\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6phavdpr1ui1a496ma8bnkjrlqlmvhcdhc.png)
As for the trigonometric function, we have to start from the parent function
and derive the graph of its child function via transformations:
- When we multiply the whole function by 2, we stretch the graph vertically. So, the function has still period
, but now it ranges from -2 to 2 instead of from -1 to 1 (amplitude 2) - When we multiply the argument by 2, we compress the function horizontally. So, the new period becomes
, and the function makes two complete oscillations from 0 to
![2\pi](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ia5d2u08w0ivg4tfm7kmao3az9h7oxlde3.png)
You can see the two functions in the image below. You can also see that the two graphs cross 4 times, meaning that the equation
has four solutions.