Answer:
∠A ≅ ∠Q because of the third angle theorem.
Explanation:
Given information: ∠B ≅ ∠N; BC ≅ NM; ∠C is right; ∠M is right.
Prove: ΔABC ≅ ΔQNM
Nessa's Proof:
In ΔABC and ΔQNM,
∠B ≅ ∠N (Given)
BC ≅ NM (Given)
∠C≅∠M (Right angles)
In both triangle two corresponding angles and there included sides are congruent. By ASA postulate
ΔABC ≅ ΔQNM
Hence proved.
Roberto's Proof:
In ΔABC and ΔQNM,
∠B ≅ ∠N (Given)
∠C≅∠M (Right angles)
∠A≅∠Q (Third angle Theorem)
BC ≅ NM (Given)
In both triangle two corresponding angles and the non-included sides are congruent. By AAS postulate
ΔABC ≅ ΔQNM
Hence proved.
Therefore, the required statement is ∠A ≅ ∠Q and the reason is third angle theorem.