Mass of Silver chloride-AgCl = 28.314 g
Further explanation
Given
1.01 L of a 0.196 M solution of Silver nitrate
Required
Mass of Silver chloride
Solution
Reaction
AgNO₃ + NaCl ⇒ AgCl + NaNO₃
mol of AgNO₃ :
mol = M x V
mol = 0.196 x 1.01
mol = 0.198
From equation, mol ratio of AgNO₃ : AgCl = 1 : 1, so mol AgCl = 0.198
mass AgCl (MW=143 g/mol) :
mass = mol x MW
mass = 0.198 x 143
mass = 28.314 g