Question

A factory worker moves a 21.0 kg crate a distance of 4.50 m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and the floor is 0.300. What magnitude of force must the worker apply? Express your answer with appropriate units.

Answer 1

61.803 Newtons

Step-by-step explanation:

m = Mass of crate = 21 kg

`\mu` = Coefficient of kinetic friction between the crate and the floor = 0.3

g = Acceleration due to gravity = 9.81 m/s²

Force

`F=\mu mg`

`\\\Rightarrow F=0.3* 21* 9.81`

`\\\Rightarrow F=61.803\ N`

So, the magnitude of force must the worker apply is 61.803 Newtons