Question

A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0500 kg bullet to accelerate it to a speed of 575 m/s in a time of 2.10 ms (milliseconds)? (Enter the magnitude.)

Answer 1

Answer:13.69 KN

Step-by-step explanation:

Given

mass of bullet
`m=0.05 kg`

Final Speed before leaving Barrel
`=575 m/s`

initial speed
`(u)=0 m/s`

time
`t=2.1 * 10^(-3) s`

we know change in momentum is equal to Impulse imparted

`Fdt=\Delta P`

where
`F=force`

`\Delta P=change\ in\ Momentum`

`dt=total\ time`

`F_(avg)* 2.1* 10^(-3)=0.05\cdot (575-0)`

`F_(avg)=13.69* 10^(3) N`

`F_(avg)=13.69 KN`