Question

Plz help me? The price of Stock A at 9 A.M. was ​$14.91. Since​ then, the price has been increasing at the rate of ​$0.06 each hour. At noon the price of Stock B was ​$15.66. It begins to decrease at the rate of ​$0.11 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

Answer 1

The prices of Stock A and Stock B will be the same after approximately 4.41 hours.

Step-by-step explanation:

To determine the number of hours it takes for the prices of Stock A and Stock B to be the same, we need to set up equations to represent the prices of each stock over time.

The price of Stock A can be represented by the equation y = 14.91 + 0.06x, where x represents the number of hours passed since 9 A.M.

The price of Stock B can be represented by the equation y = 15.66 - 0.11x, where x represents the number of hours passed since noon.

To find the number of hours where the prices are the same, we need to set the two equations equal to each other and solve for x:

14.91 + 0.06x = 15.66 - 0.11x

Combining like terms and isolating the variable, we find:

0.17x = 0.75

x ≈ 4.41

Therefore, it will take approximately 4.41 hours for the prices of Stock A and Stock B to be the same.

Answer 2

h = 4.41 hours , when they will equalize.

Step-by-step explanation:

Let the hours when they equalize=h,

14. 91 +0.06 h = 15.66 -0.11 h

0.06 h + 0.11 h = 15.66 - 14.91

0.17 h = 0.75

h =
`(0.75)/(0.17)`

h = 4.41 hours , when they will equalize.