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(a) The Eskimo pushes the same 50.0-kg sled over level ground with a force of 1.75 102 N exerted horizontally, moving it a distance of 6.00 m over new terrain. If the net work done on the sled is 1.50 102 J, find the coefficient of kinetic friction.

User Adrian May
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1 Answer

4 votes

Answer: 0.306

Step-by-step explanation:

from the question we are given the following

mass of sled (m) = 50 kg

force (f) = 1.75 x 10^2 N = 175 N

distance (s) = 6 m

net work done on the sled = 1.50 x 10 ^2 N = 150 N

acceleration due to gravity (g) = 9.8 m/s^2

coefficient of friction = μ

lets first calculate the frictional force (ff)

ff = μ x m x g = μ x 50 x 9.8 = 490 μ

work done on the slide by the applied force (W1)= f x s = 175 x 6 = 1050 j

work done on the slide by frictional force (W2) = ff x s = 490 μ x 6 = 2940μ j

now the net work done is the work done by the frictional force subtracted from the work done by the applied force

net work done = W1 - W2

150 = 1050 - 2940μ

2940μ = 1050 - 150

μ = 900 / 2940

μ = 0.306

User Ali Zia
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