109k views
5 votes
If the time from stimulus to response from the distal stimulating electrodes is 9.5ms and the time from stimulus to response from the proximal stimulating electrodes is 10.5ms and the distance between the two electrods is 55mm, what is the conduction velocity in m/s?

User Qqqqqqq
by
4.9k points

2 Answers

3 votes

Answer:

The correct answer is 55m / s

Step-by-step explanation:

Hello!

Let's solve this!

The formula for calculating speed is:

v = (x2-x1) / (t2-t1)

The data we have are:

x2 = 55mm * (1m / 1000mm) = 0.055

x1 = 0m

t2 = 10.5ms * (1s / 1000ms) = 0.0105s

t1 = 9.5ms * (1s / 1000ms) = 0.0095s

v = (0.055m) / (0.0105s-0.0095s) = 55m / s

The correct answer is 55m / s

User Rudy
by
5.2k points
3 votes

Answer:

55m/s

Step-by-step explanation:

conduction velocity (meter/second) is of a nerve is calculated by measuring the distance (millimeters) between two stimulation sites and dividing by the difference in latency (milliseconds) from the proximal.

mathematically is given as:

Conduction Velocity (meters/second) ={Distance (millimeters)}/{Proximal Latency- Distal Latency (millisecond)

C.V= (55mm)/ (10.5-9.5)ms

=55m/s

User ZedTuX
by
5.5k points