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K12 students help !!!!!!!!!!!!

K12 students help !!!!!!!!!!!!-example-1

2 Answers

7 votes
the answer is 49.07cm squared
User Rashwan L
by
8.3k points
8 votes

Explanation:

First , Split the given figure into two parts i.e rectangle and a semi - circle.

\underline{ \underline{ \text{Given}}}: [/tex]

In rectangle :

  • Length ( L ) = 14 cm
  • Width ( W ) = 9 cm

Finding the area of a rectangle :


\sf{Area \: of \: a \: rectangle = L * W}


\sf{14 \: cm * 9 \: cm}


\sf{126 \: {cm}}^(2)

Area of a rectangle = 126 cm ²

Now , In circle :

  • Diameter ( d ) = 14 cm { Since In rectangle , length of both sides are equal }
  • Radius ( r ) =
    \sf{ (14 \: cm)/(2) = 7 \: cm}


\sf{Area \: of \: a \:semi - circle = (1)/(2) \pi \: {r}}^(2)


\sf{ (1)/(2) * 3.14 * {7}^(2) }


\sf{ (1)/(2) * 3.14 * 49}


\sf{ (1)/(2) * 153.86 \: {cm}^(2) }


\sf{76.93 \: {cm}}^(2)

Area of a semi - circle = 76.93 cm²

Now , We have :

  • Area of a rectangle ( A ) = 126 cm ²
  • Area of a semi - circle ( a ) = 76.93 cm ²


\sf{Area \: of \: a \: shaded \: part = A - a}


\sf{126 \: {cm}^(2) - 76.93\: {cm}}^(2)


\boxed{ \sf{49.07 \: {cm}^(2) }}


\red{ \boxed{ \boxed{ \underline{ \sf{Our \: final \: answer : 49.07 \: {cm}^(2) }}}}}

Hope I helped ! ♡

Have a wonderful day / night ツ

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User Thomas Vanier
by
8.3k points

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