Answer:
There is a 1:1 neutralization reaction, so, number of moles:
0.085 l * 0.900 mol/ L = 0.0765 mol HCL
The heat produced: 0.0765 mol * -56.2 kJ/mol = -4.229 kJ (this is the heat of neutralization)
Change in temperature: The mass to use in the equation Q=cmT.
4229 J / (4.186 J/gC*170 g) = 6.042 C
Add to the initial temperature:
18.24 + 6.042 = 24.29 C°