Question

A 10 kg block is pushed with a constant horizontal force of 20 n against a constant horizontal frictional force of 10 n. What is the acceleration of the block?

Answer 1

The acceleration would be a=1 m/s^2. Let's explain why.

Step-by-step explanation:

Let's say the block is □

20N→□ Block is pushed with a constant horizontal force of 20N

□←10N It is known that frictional force is the opposite way of the movement

So it is safe to say that there is 10 N force trying to stop the block.

In this case our net force is
`F_(net) = 20-10=10N`

According to Newton's second motion law

`F=m.a` (m=mass, F=force, a=acceleration

`F_(net) =10=10.a` →
`a=1(m^(2) )/(s)`

As an extra information the block also applies gravitational m.g force down but since there is no other force applies in the vertical way, ground compansate the force.