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How long would it take a car with a top speed of 203 mph to travel 12.42 miles up a slope of 6.4% accelerating at 0.091 G's (2.93 ft/s sq.)

1 Answer

5 votes

Answer:

319 seconds

Explanation:

The distance 12.42 miles is equivalent to

12.42*5280=65577.6 ft


ma-mgsin\theta=ma_(net)

When slope is 6.4%,
\theta=tan^(-1) 0.064=3.67^(\circ)


a_(net)=a-gsin\theta=2.93-32.2sin3.67=-0.87

Therefore,
a_(net)=-0.87 ft/s^(2)

Also


s=ut+0.5a_(net)


65577.6=297.73t+0.5(-0.87)t^(2)


0.87t^(2)-297.73t+6577.6=0

Making t the subject of the formula by solving quadratic equation

t=318.4791278210496

Therefore, time is 319 seconds

User Jaywant Khedkar
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