Answer:
The total amount of two-dimensional space needed for the pool and its surrounding is 780 feet².
Explanation:
Consider the provided information.
The drawing uses a scale of 1 inch to 1 3/4 feet.
Now consider the figure shown.
The length and Width of the rectangle is
inch and
inch.
![22(2)/(7)=(156)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yf9g3a26c0cbx05thlhjqs4co9sjx3qr54.png)
![11(3)/(7)=(80)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vrhv2u40sx2nm3qibgawtpf55g0wzce29n.png)
First convert the length and width from inches to feet.
![1\ inch=1(3)/(4)\ feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/npxmj801hhae5c2bg9w4h4welnlg28jdzf.png)
![1\ inch=(7)/(4)\ feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kk7cdkbv8a82g6trnqi33v3ivhkwqbtv6m.png)
Multiply both the sides by
![(156)/(7)\ inch=(156)/(7)* (7)/(4)\ feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o0vuqn07z2pl8jnuy74829griinbzpbuts.png)
![(156)/(7)\ inch=39\ feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/al2bq3x8kaiytl0kc014586jh9nhptfkh0.png)
Now convert
into feet.
![(80)/(7)\ inch=(80)/(7)* (7)/(4)\ feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zea0iod6oz1m2e6wo57l7vbcmjk057uow0.png)
![(80)/(7)\ inch=20\ feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dh18rw1iw408ppfvfnz13w3k68e9ls6exq.png)
Now find the area of rectangle using the formula.
![A=l* w](https://img.qammunity.org/2020/formulas/mathematics/high-school/635p0kd3l22klexa3uw166lpcz3c3u5e3j.png)
![A=39* 20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h0cv08sej2oufxwg9fwaz4sczryx29fk2l.png)
![A=780](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jlzwz1k6nbuf2nokt96atpr6rbfefwh3wz.png)
Hence, the total amount of two-dimensional space needed for the pool and its surrounding is 780 feet².