Answer:
The width of the room is
.
Explanation:
Consider the provided information.
It is given that the whole room has an area 46 14/15 sq yd.
This can be written as:
yd.
Now consider the figure shown below:
From the figure we know that the length of the rectangular meeting room is
yd.
![7(1)/(3)=(22)/(3)](https://img.qammunity.org/2020/formulas/mathematics/college/8el3b6dh177v02pm77n9neoksdbj5ga89p.png)
The area of rectangle is
![A=l* w](https://img.qammunity.org/2020/formulas/mathematics/high-school/635p0kd3l22klexa3uw166lpcz3c3u5e3j.png)
Let width of the rectangle is w yard.
![(704)/(15)=(22)/(3)* w](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9tdsheb0hidi6yqoig8ei2w7ypcthx14zx.png)
![w=(704)/(15)* (3)/(22)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i9idrccs6s7fi1jw5kjk0v2n6ol93jkvx6.png)
![w=(32)/(5)=6(2)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/um3jgchq5s2b1vfdv3ltzpiiawt1641dxp.png)
Hence, the width of the room is
.