Question

A football is thrown at an angle of 44◦ above the horizontal. Assume the ball is throw and received at the same height. To throw a 55.7 m pass, what must be the initial speed of the ball? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of m/s.

Answer 1

The initial speed of the ball is 23.3 m/s.

Step-by-step explanation:

Given that,

Angle = 44°

Range = 55.7 m

We need to calculate the initial speed of the ball

Using formula of range

`R=(u^2\sin2\theta)/(g)`

Where. u = initial velocity

r = range

g = acceleration due to gravity

Put the value into the formula

`55.7=(u^2\sin2*44)/(9.8)`

`u^2=(55.7*9.8)/(\sin88)`

`u=\sqrt{(55.7*9.8)/(\sin88)}`

`u=23.3\ m/s`

Hence, The initial speed of the ball is 23.3 m/s.