Question

In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above the launch point that is four times greater than that of ball b. The launch speed of ball a is _______ times greater than that of ball b.

Answer 1

Va is two times greater than Vb

Step-by-step explanation:

The maximum height reached by the balls are:

`Ymax = (Vo^2)/(2g)`

Since we are told that Ya = 4Yb:

`Ya =  (Va^2)/(2g) = 4* Yb = 4 * (Vb^2)/(2g)`

Simplifying the equation:

`Va^2 = 4*Vb^2`

`Va = 2*Vb`