Question

Jim rides his skateboard down a ramp that is in the shape of a quarter circle with a radius of 5.00 m. At the bottom of the ramp, Jim is moving at 9.00 m/s. Jim and his skateboard have a mass of 58.4 kg. How much work is done by friction as the skateboard goes down the ramp?

Answer 1

The work done by friction can be calculated using the equation: Work = force * distance. The force of friction can be calculated using the equation: Force of friction = coefficient of friction * Normal force. Once we have the force of friction and the displacement of the skateboard along the ramp, we can calculate the work done by multiplying these two values.

Step-by-step explanation:

In order to calculate the work done by friction, we can use the equation:

Work = force * distance

The force of friction can be calculated using:

Force of friction = coefficient of friction * Normal force

In this case, the normal force is equal to the weight of Jim and his skateboard, which is given by:

Normal force = mass * acceleration due to gravity

Once we have the force of friction and the displacement of the skateboard along the ramp, we can calculate the work done by multiplying these two values.

Answer 2

Wfr=-496.4 J

Step-by-step explanation:

The total work of the motion is describe

x=5.0m

v=9.0 m/s

m=58.4kg

`W_(total)=W_(g)+W_(fr)`

`W_(total)=(1)/(2)*m*(v_(f))^(2)\\W_(g)=m*g*x`

The Work of the friction can be find without know the coefficient however knowing the total work and the work done by the gravity down a ramp can find the work of the friction

`W_(fr)=W_(total)-W_(g)\\W_(fr)=(1)/(2)*m*(v_(f))^(2)-m*g*x`

`W_(fr)=(1)/(2)*58.4kg*(9(m)/(s))^(2)-58.4kg*9.8(m)/(s^(2))*(0m-5m)\\W_(fr)=-496.4 J`