Question

An electrical heater is used to add 22.00 kJ of heat to a constant-volume calorimeter. The temperature of the calorimeter increases by 3.24°C. When 1.75 g of propanol (C3H7OH) is burned in the same calorimeter, the temperature increases by 8.66°C. Calculate the molar heat of combustion for propanol (enter in kJ).

Answer 1

The molar heat of combustion for propanol is 2020.62 kJ/mol

Step-by-step explanation:

Step 1: Data given

heat added = 22.00 kJ

Temperature increases with 3.24 °C

When 1.75 grams of propanol is burned, temperature increases with 8.66 °C

Step 2: Calculate energy released per °C

22 kJ / 3.24 °C = 6.79 kJ/°C

Step 3: Calculate the energy released for the combustion of propanol

6.79 kJ/ °C * 8.66 °C = 58.8 kJ

Step 4: Calculate number of moles of propanol

Number of moles = mass of propanol / Molar mass of propanol

Number of moles = 1.75 grams / 60.09 g/mole

Number of moles = 0.0291 moles

Step 5: Calculate the molar heat of combustion for propanol

58.8 kJ / 0.0291 moles = 2020.62 kJ/mol

The molar heat of combustion for propanol is 2020.62 kJ/mol