Question

how much work does f⃗ do when the proton moves along the straight-line path from the point (0.10m,0) to the point (0.30m,0) ?

Answer 1

The work done by the force is 10 units.

Step-by-step explanation:

The work done by a force is given by the equation:

Work = Force × Displacement × cos(θ)

Where:

• Force is the magnitude of the force vector
• Displacement is the magnitude of the displacement vector
• θ is the angle between the force and displacement vectors

In this case, the force vector F = (2y)i + (3x)j

The displacement vector is given as (Δx,Δy) = (5 m, 0 m)

The angle between the two vectors is θ = 0 degrees, since both vectors are in the same direction.

Therefore, we can calculate the work done by substituting the given values into the work equation:

Work = Force × Displacement × cos(θ)

Work = ((2y)(5) + (3x)(0)) × (5) × cos(0)

Work = 10